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<table border="0" cellpadding="3" cellspacing="1" width="100%" class="forumline"> <tr> <th class="thCornerL" width="22%" height="26">Autor</th> <th class="thCornerR">Wiadomość</th> </tr> <tr> <td width="22%" align="left" valign="top" class="row1"><span class="name"><a name=""></a><b>iene48622f</b></span></td> <td class="row1" height="28" valign="top"><table width="100%" border="0" cellspacing="0" cellpadding="0"> <tr> <td width="100%"><img src="http://picsrv.fora.pl/Aniseed/images/icon_minipost.gif" width="12" height="9" alt="Post" title="Post" border="0" /><span class="postdetails">Wysłany: Wto 4:54, 19 Kwi 2011<span class="gen"> </span> Temat postu: How To Understand Audio Components Part Ii</span></td> </tr> <tr> <td colspan="2"><hr /></td> </tr> <tr> <td colspan="2"><span class="postbody">formula for current is I = V divided by R. If the resistance is kept constant in a circuit, and the voltage is varied, the current is varied in the same proportion. An example of this can be watched in a light lamp. If the light bulb has 10 volts applied to it, a measure will indicate the current by that voltage. As the voltage decreases, the current decreases and makes the light lamp dimmer. I is the amount of current through the resistance across the source of latent feud, or voltage. There has to be a resistance between the plus side,<a href="http://www.objordans.com/air-jordan-take-flight" target="_blank" class="postlink">http://www.objordans.com/air-jordan-take-flight</a>, and minus side of a battery. Anyone who has touched both ends of jumper cables attach proves this. It is called a straight short to floor in a circuit. Lets join a 8 Ohm resistor across the and & Minus <br />side of a 12V power cell. How much is the current I. I = 12V divided by R of 8 Ohm's = 1.5A or amps as I. <br />Voltage is calculated by the formula V = I x R. If I equals 1.5A, and R = 3 Ohm's, the voltage will be 4.5V across the resistor. <br />The formula for resistance is R = V divided by I. <br />This is the third and terminal edition of Ohm's statute. Let's prove the relationship among these three ingredients of Ohm's statute, In the last problem, voltage was equal apt 4.5V. We also know thatI = 1.5A, and R = 3 Ohm's. 4.5v divided by 1.5A, has a resistance of 3 Ohm's, proving this relationship. <br /> In conclusion, now, you understand how to reckon, I,<a href="http://www.objordans.com/air-jordan-flight-tr" target="_blank" class="postlink">http://www.objordans.com/air-jordan-flight-tr</a>, R, and V in a circle. We studied namely by knowing 2 factors, the third tin be calculated using Ohm's law. We also proved, there is a relationship between always three factors. <br />In my next article, you ambition learn elements of calculation for calculating,<a href="http://www.objordans.com/air-jordan-hardcourt-classic" target="_blank" class="postlink">http://www.objordans.com/air-jordan-hardcourt-classic</a>, mega, kilo, milli, and micro. In counting, we ambition learn how to calculate power & power dissipation in resistance. <br />Problems for this article: <br />1. With 10V along an R of 5 Ohm's what namely the current I? <br />2. When 10V produces 2.5A, R is equal to? <br />3. With 8A through a 2 ohm resistor, the I x R voltage is? <br />If you absence to check your questions to these problems, check out the treatises page on our website. Thank you & numerous blessings to you. Bradley Angell</span></td> </tr> </table></td> </tr> <tr> <td colspan="2" height="1" class="spaceRow"><img src="http://picsrv.fora.pl/Aniseed/images/spacer.gif" alt="" width="1" height="1" /></td> </tr> </table>
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